2x^2+2x-kx+8=0

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Solution for 2x^2+2x-kx+8=0 equation:


Simplifying
2x2 + 2x + -1kx + 8 = 0

Reorder the terms:
8 + -1kx + 2x + 2x2 = 0

Solving
8 + -1kx + 2x + 2x2 = 0

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -1kx + 2x + -8 + 2x2 = 0 + -8

Reorder the terms:
8 + -8 + -1kx + 2x + 2x2 = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -1kx + 2x + 2x2 = 0 + -8
-1kx + 2x + 2x2 = 0 + -8

Combine like terms: 0 + -8 = -8
-1kx + 2x + 2x2 = -8

Add '-2x' to each side of the equation.
-1kx + 2x + -2x + 2x2 = -8 + -2x

Combine like terms: 2x + -2x = 0
-1kx + 0 + 2x2 = -8 + -2x
-1kx + 2x2 = -8 + -2x

Add '-2x2' to each side of the equation.
-1kx + 2x2 + -2x2 = -8 + -2x + -2x2

Combine like terms: 2x2 + -2x2 = 0
-1kx + 0 = -8 + -2x + -2x2
-1kx = -8 + -2x + -2x2

Divide each side by '-1x'.
k = 8x-1 + 2 + 2x

Simplifying
k = 8x-1 + 2 + 2x

Reorder the terms:
k = 2 + 8x-1 + 2x

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